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- fixed all the laser preprocessors to work correctly and the resulting GCode to be plotted

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- made sure that when drilling and milling with a `laser` preprocessor the first move is not done with the laser on
This commit is contained in:
Marius Stanciu
2022-01-31 00:04:49 +02:00
committed by Marius
parent 262e795f2e
commit 7420ac9fd5
9 changed files with 76 additions and 62 deletions
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22
preprocessors/Marlin_laser_Spindle_pin.py
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@@ -63,14 +63,12 @@ class Marlin_laser_Spindle_pin(PreProc):
def lift_code(self, p):
if float(p.laser_min_power) > 0.0:
return 'M3 S%s' % str(p.laser_min_power)
# the formatted text: laser OFF must always be like this else the plotting will not be done correctly
return 'M3 S%s ;laser OFF\n' % str(p.laser_min_power)
else:
if float(p.laser_min_power) > 0.0:
return 'M3 S%s' % str(p.laser_min_power)
else:
gcode = 'M400\n'
gcode += 'M5'
return gcode
gcode = 'M400\n'
gcode += 'M5'
return gcode
def down_code(self, p):
if p.spindlespeed:
@@ -82,12 +80,7 @@ class Marlin_laser_Spindle_pin(PreProc):
return ''
def up_to_zero_code(self, p):
if float(p.laser_min_power) > 0.0:
return 'M3 S%s' % str(p.laser_min_power)
else:
gcode = 'M400\n'
gcode += 'M5'
return gcode
return ''
def position_code(self, p):
# formula for skewing on x for example is:
@@ -143,7 +136,8 @@ class Marlin_laser_Spindle_pin(PreProc):
def spindle_stop_code(self, p):
if float(p.laser_min_power) > 0.0:
return 'M3 S%s' % str(p.laser_min_power)
# the formatted text: laser OFF must always be like this else the plotting will not be done correctly
return 'M3 S%s ;laser OFF\n' % str(p.laser_min_power)
else:
gcode = 'M400\n'
gcode += 'M5'